For example:

`x + 1 < 2` -> `x < 2 - 1`

If we can prove that `x + 1` does not overflow and `2 - 1` does not overflow.

Consider this more practical example:

```
public void foo(int[] arr) {
  for (i = arr.length - 1; i >= 0; --i) {
    blackhole(arr[i]);
  }
}
```

C2 emits a loop guard that looks `arr.length - 1 < 0`. We know `arr.length - 1` does not overflow because `arr.length` is positive. We can fold the comparison into `arr.length < 1`. We have to compute `arr.length - 1` computation if we enter the loop anyway, but we can avoid the subtraction computation if we exit the loop. I believe the simplification can also help with stronger integer range analysis in https://bugs.openjdk.org/browse/JDK-8275202.