public static class Sup {
   <T extends Runnable & Cloneable> void m(T arg) { System.out.println("Sup"); }
 }
 public static class Sub extends Sup {
   <T extends Cloneable & Runnable> void m(T arg) { System.out.println("Sub"); }
 }

Internally, the compiler treats this as an override.  But the generated code includes Sup.m(Runnable)V and Sub.m(Cloneable)V, with no bridge between them.

ecj 3.8 has the same typing logic, but does generate a bridge.

Another possible (source-incompatible) approach is to decide that the two intersections are _not_ the same, so no overriding occurs.  JLS is not extremely clear on this.