Please see minimized test below:

$ cat test.java
import java.lang.invoke.MethodType;
import static java.lang.invoke.MethodHandles.*;
import static java.lang.invoke.MethodHandles.Lookup.*;

public class test {

    public static void main(String[] args) throws Throwable {
        lookup().findGetter(TestCls.class, "f2", int.class);
        TestCls c =  new TestCls();
        c.f2 =  1;
    }
}

class TestCls {
    protected int f2 = 2;
}

$ javac test.java
$ java -showversion test
java version "1.7.0-ea"
Java(TM) SE Runtime Environment (build 1.7.0-ea-b140)
Java HotSpot(TM) Server VM (build 21.0-b10, mixed mode)

Exception in thread "main" java.lang.IllegalAccessException: caller class must be a subclass below the method: TestCls.f2/int, from class test
        at java.lang.invoke.MemberName.makeAccessException(MemberName.java:507)
        at java.lang.invoke.MethodHandles$Lookup.restrictReceiver(MethodHandles.java:1078)
        at java.lang.invoke.MethodHandles$Lookup.restrictProtectedReceiver(MethodHandles.java:1072)
        at java.lang.invoke.MethodHandles$Lookup.makeAccessor(MethodHandles.java:1104)
        at java.lang.invoke.MethodHandles$Lookup.makeAccessor(MethodHandles.java:1094)
        at java.lang.invoke.MethodHandles$Lookup.findGetter(MethodHandles.java:724)
        at test.main(test.java:8)
Note that findSetter has the same issue.