JDK-6598160 : Windows IPv6 Socket implementation doesn't set the handle to not inherit
- Type: Bug
- Component: core-libs
- Sub-Component: java.net
- Affected Version: 5.0,6
- Priority: P4
- Status: Resolved
- Resolution: Fixed
- OS: windows_2003,windows_xp
- CPU: x86
- Submitted: 2007-08-28
- Updated: 2010-04-02
- Resolved: 2007-09-15
The Version table provides details related to the release that this issue/RFE will be addressed.
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Fixed : Release in which this issue/RFE has been fixed. The release containing this fix may be available for download as an Early Access Release or a General Availability Release.
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Unresolved : Release in which this issue/RFE will be addressed.
Resolved: Release in which this issue/RFE has been resolved.
Fixed : Release in which this issue/RFE has been fixed. The release containing this fix may be available for download as an Early Access Release or a General Availability Release.
To download the current JDK release, click here.
| Other | Other | JDK 6 | JDK 7 |
|---|---|---|---|
| 5.0u17-revFixed | 5.0u19Fixed | 6u10Fixed  |
7 b21Fixed |
Description
See http://forums.java.net/jive/thread.jspa?threadID=29654&tstart=0
You can reproduce this issue running on Windows XP or 2003 with IPv6 enabled.
--- begin code ---
public class SockTest
{
public static void main(String[] args) throws Exception {
ServerSocket ss = new ServerSocket(4444);
Runtime.getRuntime().exec(new String[] {"notepad.exe"});
ss.close();
}
}
--- end code ---
The above testcase spawns a notepad. Notepad inherits the handle to the socket, so if you try and re-execute the test if fails with "BindException: Address already in use".
This is reproducible with Java SE 5, 6, and 7.
Comments
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