If I try to call method handle for a virtual method without binding it to an object, the exception message says the following:

java.dyn.WrongMethodTypeException: (Ljava/lang/String;Ljava/lang/Integer;F)J cannot be called as (Ljava/lang/String;Ljava/lang/Integer;F)J
        at jsr292test01.main(jsr292test01.java:24)

This is confusing for a user: signatures do match, why wrong type?

Test program:

$ cat jsr292test01.java
import java.dyn.MethodHandle;
import java.dyn.MethodHandles;
import java.dyn.MethodType;

public class jsr292test01 {
	
	public long method(String a, Integer b, float c) {
		return 0;
	}

	public static void main(String[] args) {
		try {
			MethodHandle mh = MethodHandles.lookup().findVirtual(jsr292test01.class, "method",
					MethodType.methodType(long.class, String.class, Integer.class, float.class));
			
			jsr292test01 me = new jsr292test01();
			long l;
			
			System.err.println("1");
			l = (long) mh.bindTo(me).invokeExact("a", new Integer(1), 3F); // OK

			System.err.println("2");
			l = (long) mh.invokeExact("a", new Integer(1), 3F); // Exception
			
		} catch ( Throwable t ) {
			t.printStackTrace();
		}
	}

}
$